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哪位大侠能帮忙解决:将直径1.5mm钛镍合金丝折弯90度,过渡半径R20mm,保持超弹性性能。 |
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小黑屋|手机版|Archiver|机械社区 ( 京ICP备10217105号-1，京ICP证050210号，浙公网安备33038202004372号 )
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发表于 2016-7-15 17:48:55