2266998 发表于 2011-10-25 12:22 / \4 z( ?: L' b; s* R" V
齿轮与滚刀位置定了,理论上的啮合点就定了,啮进、啮出就是确定的了,既然你有了共轭线,就应当有了交点, ...
" j! u6 J8 g4 w8 f. K方程这样的
0 k8 z$ H" J. r* a, N5 F; f xat = ((r - r * Sin(αn) - ha) * Tan(αn) - sn1) / Cos(β)/ F" h2 k* @# k4 \, F7 C
xbt = (-sn1 / 2 + (h - ha) * Tan(αn)) / Cos(β)
5 s9 \" R1 V4 f7 m# ~ yat = r - r * Sin(αn) - ha
( L: E; u6 P5 h) Q% a# T x1 = λa* Q; Q& Y w0 `
y1 = yat + (λa - xat) * Atan(αn) * Cos(β)( I) N& C v8 z1 d8 b1 M* B9 `% X
ψ = (x1 + y1 * Atan(αn) * Cos(β)) / r1
: M7 B# B) u" g0 F/ R; ]1 n& N, E x2 = Cos(ψ) * x1 + Sin(ψ) * y1 + r1 * (Sin(ψ) - ψ * Cos(ψ)): j6 }7 M" j% P" q: c3 q
y2 = -Sin(ψ) * x1 + Cos(ψ) * y1 + r1 * (Cos(ψ) + ψ * Sin(ψ)), v% {- O4 o- y" z8 f3 E( l
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xet = xat - r * Cos(αn) / Cos(β)8 x7 ?& f( E$ y0 f. J
x3 = xet + r * Sin(λe) / Cos(β)! E+ Z1 e; W: V; ~2 z4 X6 `
y3 = -ha + r - r * Cos(λe)- w( V) l; X, }8 g. \/ n: ]& `3 Y, R; F
ψ1 = (x3 + y3 * Atan(αn) * Cos(β)) / r1
% O/ Z* |8 v/ N! N+ J- H1 s4 N$ t x4 = Cos(ψ1) * x3 + Sin(ψ1) * y3 + r1 * (Sin(ψ1) - ψ1 * Cos(ψ1))
; J. \1 Y# C2 o- t/ | y4 = -Sin(ψ1) * x3 + Cos(ψ1) * y3 + r1 * (Cos(ψ1) + ψ1 * Sin(ψ1))( I7 \. [4 \6 Q3 @
λa,λe是在一定的范围内,联立方程组怎么解啊
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