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设一对中心距为110的齿轮 齿数比为6:5 则大齿轮的参数方程为:x=60*(cos(t)+t*sin(t)) y=60*(sin(t)-t*cos(t)) 根据啮合原理 利用matlab编程
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>> x=60*(cos(t)+t*sin(t))2 H& R$ O) c* V) `8 A0 `
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. y% h4 S5 E9 p9 X9 A! _( wx =
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60*cos(t) + 60*t*sin(t)! a" e8 H( F% n. ^0 q: L6 A: q
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, q3 O0 \! y$ r0 ^>> y=60*(sin(t)-t*cos(t))
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y =
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- b' N9 ]( E u; l60*sin(t) - 60*t*cos(t)
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>> x1=-x*cos(11/6*q)-y*sin(11/6*q)+110*cos(q)0 `( i8 P& _4 B& r
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x1 =% u, w- Q! A" I) D, G" ~. X; ?8 {* n: e L+ b
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110*cos(q) - cos((11*q)/6)*(60*cos(t) + 60*t*sin(t)) - sin((11*q)/6)*(60*sin(t) - 60*t*cos(t))
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>> y1=-x*sin(11/6*q)+y*cos(11/6*q)+110*sin(q)- G3 q* t" b0 A( q1 s7 Z
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$ h) B" c: g, Z* J Xy1 =2 }! Q) l! l# N% N0 B, v
/ U# H+ h0 @ ^" n4 D7 z: k110*sin(q) + cos((11*q)/6)*(60*sin(t) - 60*t*cos(t)) - sin((11*q)/6)*(60*cos(t) + 60*t*sin(t))& g0 z5 I5 B9 D2 w; e
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>> diff(x1,t)* J3 H( O7 A" k; {+ x
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ans =# M- O0 b. G# g9 O# F
: Z5 j' i4 e% q7 Z- 60*t*cos((11*q)/6)*cos(t) - 60*t*sin((11*q)/6)*sin(t)" v9 m# E+ O* ?: k6 f7 P: Z; A7 _2 ?% n, B+ Y9 w7 @
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3 m% ?2 t/ i( r3 p. s>> diff(y1,t)+ N! `! Q( i3 @% n9 o- D* l% L6 q7 d( X) I: h+ i, x
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60*t*cos((11*q)/6)*sin(t) - 60*t*sin((11*q)/6)*cos(t)$ F; D4 J5 g2 e) o
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( D! s7 A, P: u* t* b2 q. k, [>> diff(x1,q)) Y8 ~0 j& o6 y$ k) K& @
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ans =$ Y* Q4 m& Q4 m" e. N
: h: b, X: \$ w( V(11*sin((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6 - (11*cos((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6 - 110*sin(q)' u n: a4 ~( Q# G, W6 I
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ans =7 _* e5 n( |# T5 D) I% J, r: d
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110*cos(q) - (11*cos((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6 - (11*sin((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6& D- j$ V; g# f
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6 ~/ a% j ?' {0 L/ g) i$ s5 T>> f1=sym('(110*cos(q) - (11*cos((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6 - (11*sin((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6)*(- 60*t*cos((11*q)/6)*cos(t) - 60*t*sin((11*q)/6)*sin(t))-((11*sin((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6 - (11*cos((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6 - 110*sin(q))*(60*t*cos((11*q)/6)*sin(t) - 60*t*sin((11*q)/6)*cos(t))')1 C v! U' ]' ^5 K
0 S* L' u4 d3 Q. d# Yf1 =
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2 [. R- C3 P. `(60*t*cos((11*q)/6)*cos(t) + 60*t*sin((11*q)/6)*sin(t))*((11*cos((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6 - 110*cos(q) + (11*sin((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6) + (60*t*cos((11*q)/6)*sin(t) - 60*t*sin((11*q)/6)*cos(t))*(110*sin(q) + (11*cos((11*q)/6)*(60*sin(t) - 60*t*cos(t)))/6 - (11*sin((11*q)/6)*(60*cos(t) + 60*t*sin(t)))/6)) r) R- G3 z4 L n& b
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>> simplify(f1)) [ m8 o C& N b2 a/ @
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3 e7 X. v& P5 ians =4 i' A% H% c% V; u# N# ~4 ?
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! V. v0 T8 _! K Y2 t+ A9 K-6600*t*(cos((5*q)/6 - t) - 1)/ C G& R$ P1 @- K7 |, E
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( ^8 j# E3 Q& b& A" h4 ~7 h' X# B-6600*t*(cos((5*q)/6 - t) - 1)=0 解得q=6/5*t 代入 x1=-x*cos(11/6*q)-y*sin(11/6*q)+110*cos(q) * q1 K: y3 z1 G3 m4 N- }% z2 A+ J6 L( `" R* T z/ o' K3 t5 Z3 f. `
y1=-x*sin(11/6*q)+y*cos(11/6*q)+110*sin(q)
* p# s: w: |, T- y! {6 i3 V化简后得X1=50*(cos(1.2*t)+1.2*t*sin(1.2*t)) y=50*(sin(1.2*t)-1.2*t*cos(1.2*t))' A' F+ s& b8 e$ H9 ~
从方程上可以看出小齿轮的方程仍为渐开线
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