本人的毕业设计：关于UG的二次开发运用（GRIP语言编程）

fewofj 发表于 2011-5-27 20:21:14

本帖最后由 fewofj 于 2011-5-27 20:27 编辑

下面是关于凸轮的一个运动轨迹的编程，只要把程序导入到UG中就可以实现凸轮的运转，还可以修改程序中各个凸轮的参数来实现各种凸轮的运转。组合运动规律
ENTITY/pt(360),spln(4),PT1,CR1,CR2,ext
NUMBER/J(360),S(360),X(360),Y(360),i,m,e,n
DATA/i,1,m,1,e,1,n,1$$赋值
l30:
PARAM/'凸轮参数',$
'升程（h）',h,$
'基圆半径（R0）',R0,$
'滚子半径（Rr）',Rr,$
'推程转角（Angle1）',Angle1,$
'远休止角（Angle2）',Angle2,$
'回程转角（Angle3）',Angle3,$
'近休止角（Angle4）',Angle4,$
respond
JUMP/l30:,stop:,,respond
MESSG/'您已输入完参数！'
l00:
CHOOSE/'选择推程运动规律',$
'一次多项式推程','二次多项式推程','五次多项式推程',$
'简谐运动推程','摆线运动推程',$
DEFLT,1,respond
JUMP/l00:,stop:,,,lab1:,lab2:,lab3:,lab4:,lab5:,respond
l20:
CHOOSE/'选择回程运动规律',$
'一次多项式回程','二次多项式回程','五次多项式回程',$
'简谐运动回程','摆线运动回程',$
DEFLT,1,respond
JUMP/l20:,stop:,,,lab6:,lab7:,lab8:,lab9:,lab10:,respond
lab1:
MESSG/'一次多项式推程'
LAA:
IFTHEN/i<Angle1+2
J(i)=i-1
S(i)=h*J(i)/Angle1
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
pt(i)=POINT/X(i),Y(i),Z
i=i+1
JUMP/LAA:
ENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
JUMP/l20:
lab2:
MESSG/'二次多项式推程'
$$推程等加速阶段
LBB:
IFTHEN/i<Angle1/2+2
J(i)=i-1
S(i)=2*h*J(i)*J(i)/(Angle1*Angle1)
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
pt(i)=POINT/X(i),Y(i),Z
i=i+1
JUMP/LBB:
ENDIF
spln(1)=SPLINE/pt(1..Angle1/2+1)
DELETE/pt(1..Angle1/2+1)
$$推程等减速阶段
LCC:
IFTHEN/e<Angle1/2+2
J(e)=e+Angle1/2-1
S(e)=h-2*h*(Angle1-J(e))*(Angle1-J(e))/(Angle1*Angle1)
X(e)=(R0+S(e))*cosf(J(e))
Y(e)=(R0+S(e))*sinf(J(e))
Z=0
pt(e)=POINT/X(e),Y(e),Z
e=e+1
JUMP/LCC:
ENDIF
spln(2)=SPLINE/pt(1..Angle1/2+1)
DELETE/pt(1..Angle1/2+1)
JUMP/l20:
lab3:
MESSG/'五次多项式推程'
LDD:
IFTHEN/i<Angle1+2
J(i)=i-1
Q=J(i)/Angle1
S(i)=h*(10*Q*Q*Q-15*Q*Q*Q*Q+6*Q*Q*Q*Q*Q)
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
pt(i)=POINT/X(i),Y(i),Z
i=i+1
JUMP/LDD:
ENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
JUMP/l20:
lab4:
MESSG/'简谐运动推程'
LEE:
IFTHEN/i<Angle1+2
J(i)=i-1
S(i)=h*(1-cosf(180*J(i)/Angle1))/2
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
pt(i)=POINT/X(i),Y(i),Z
i=i+1
JUMP/LEE:
ENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
JUMP/l20:
lab5:
MESSG/'摆线运动推程'
LFF:
IFTHEN/i<Angle1+2
J(i)=i-1
S(i)=h*(J(i)/Angle1-sinf(360*J(i)/Angle1)/6.2832)
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
pt(i)=POINT/X(i),Y(i),Z
i=i+1
JUMP/LFF:
ENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
JUMP/l20:
lab6:
MESSG/'一次多项式回程'
LHH:
IFTHEN/m<Angle3+2
J(m)=m+Angle1+Angle2-1
S(m)=h-h*(J(m)-Angle1-Angle2)/Angle3
X(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
Z=0
pt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LHH:
ENDIF
spln(2)=SPLINE/pt(1..Angle3+1)
DELETE/pt(1..Angle3+1)
JUMP/l40:
lab7:
MESSG/'二次多项式回程'
$$回程等减速阶段
LII:
IFTHEN/m<Angle3/2+2
J(m)=m+Angle1+Angle2-1
S(m)=h-2*h*(J(m)-Angle1-Angle2)*(J(m)-Angle1-Angle2)/(Angle3*Angle3)
X(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
Z=0
pt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LII:
ENDIF
spln(3)=SPLINE/pt(1..Angle3/2+1)
DELETE/pt(1..Angle3/2+1)
$$回程等加速阶段
LKK:
IFTHEN/n<Angle3/2+2
J(n)=n+Angle1+Angle2+Angle3/2-1
Q=Angle1+Angle2+Angle3
S(n)=2*h*(Q-J(n))*(Q-J(n))/(Angle3*Angle3)
X(n)=(R0+S(n))*cosf(J(n))
Y(n)=(R0+S(n))*sinf(J(n))
Z=0
pt(n)=POINT/X(n),Y(n),Z
n=n+1
JUMP/LKK:
ENDIF
spln(4)=SPLINE/pt(1..Angle3/2+1)
DELETE/pt(1..Angle3/2+1)
JUMP/l40:
lab8:
MESSG/'五次多项式回程'
LRR:
IFTHEN/m<Angle3+2
J(m)=m+Angle1+Angle2-1
W=(J(m)-Angle1-Angle2)/Angle3
S(m)=h-h*(10*W*W*W-15*W*W*W*W+6*W*W*W*W*W)
X(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
Z=0
pt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LRR:
ENDIF
spln(2)=SPLINE/pt(1..Angle3+1)
DELETE/pt(1..Angle3+1)
JUMP/l40:
lab9:
MESSG/'简谐运动回程'
LWW:
IFTHEN/m<Angle3+2
J(m)=m+Angle1+Angle2-1
S(m)=h*(1+cosf(180*(J(m)-Angle1-Angle2)/Angle3))/2
X(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
Z=0
pt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LWW:
ENDIF
spln(2)=SPLINE/pt(1..Angle3+1)
DELETE/pt(1..Angle3+1)
JUMP/l40:
lab10:
MESSG/'摆线运动回程'
LQQ:
IFTHEN/m<Angle3+2
J(m)=m+Angle1+Angle2-1
A=J(m)-Angle1-Angle2
S(m)=h*(1-A/Angle3+sinf(360*A/Angle3)/6.2832)
X(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
Z=0
pt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LQQ:
ENDIF
spln(2)=SPLINE/pt(1..Angle3+1)
DELETE/pt(1..Angle3+1)
JUMP/l40:
l40:
$$远休止角
PT1=POINT/0,0
CR1=CIRCLE/CENTER,PT1,RADIUS,R0+h,START,Angle1,END,Angle1+Angle2
$$近休止角
CR2=CIRCLE/CENTER,PT1,RADIUS,R0,START,Angle1+Angle2+Angle3,END,0
JUMP/stop:
stop:
halt

好多图片不能上传，如有需要的话。把邮箱给我，我可以发给他

78273928 发表于 2011-6-9 11:11:01

13793371086@163.com 不胜感激

fewofj 发表于 2011-6-14 21:34:43

回复 78273928 的帖子

马上发给你。如果收不到可以QQ联系我：532131146

78273928 发表于 2011-6-14 22:38:31

回复 fewofj 的帖子

谢谢收到了学习一下

xiaowuzh 发表于 2011-6-19 10:51:02

回复 fewofj 的帖子

楼主我邮箱的xiaowuzhi@126.com。发给我一份吧，谢谢。

zaq8577 发表于 2011-8-1 15:19:45

谢谢，正想了解一下 zaq8577@163.com

holland930 发表于 2011-8-3 11:19:14

799350380@qq.com不胜感激谢谢！

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本人的毕业设计：关于UG的二次开发运用（GRIP语言编程）